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world:marcinkiewicz

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2023/11/14 18:37

$g$-lemma

Let be a random variable non-negative a.s. and an increasing differentiable function such that . Then,

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Write, using that for , ,

Convexity inequality

Let , and real-valued random variables. Then, by convexity

Marcinkiewicz–Zygmund inequality

Let , and centered independent real-valued random variables in . Then, there exists a universal constant depending only on such that

Proof

Set . Let . We first establish an upper-bound for .

Let and define for all , and . Then, Let . The Chernoff bound and the independence of the by independence of the both provide Using the Taylor formula with the exponential function yields that the function defined on by is increasing, and together with for all , we deduce The fact that implies and thus . Combining with yields for all , Together with \eqref{eq:s_n_t_n} and \eqref{eq:t_n_only} this provides where . Note that implies that the are all equal to zero a.s., a situation where the inequality is trivially true, and we can thus assume . The argument of the exponential in \eqref{eq:s_n_step_1} is then minimized in at , with

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The function defined on by is continuous, diverges to infinity when , and its derivative has a unique zero on defined by .

With where , combining with \eqref{eq:s_n_step_1} yields Considering provides a similar inequality for , and using the fact that we deduce

Using the $g$-lemma with we deduce with the change of variables . The integral is finite iff , and we can choose to deduce the Rosenthal inequality: where only depends on . Finally, by Jensen inequality as , and by convexity,

which together with the Rosenthal inequality \eqref{eq:rosenthal} yields the Marcinkiewicz–Zygmund inequality: where .

Generalized Marcinkiewicz–Zygmund inequality

Let and a norm on . Let and independent random variables of with . Then, where is a constant depending only on and on the choice of the norm .

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First, notice that the result only needs to be proved for centered random variables. Indeed, by convexity, for any random variable , Moreover, by equivalence of norms in finite dimension, the result only needs to be proved for the norm on . Using the Marcinkiewicz–Zygmund inequality in dimension 1 provides

Some notation

Reminder of the notation introduced in Fort, Moulines (2003) p.12.

Let , a sequence of random variables and a sequence of nonzero real numbers. We write if is bounded in .

$O$-lemma

Let and a sequence of random variables such that with . Then,

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By assumption, there exists such that for all , .

Let . By Markov inequality, for all , hence By Borel-Cantelli lemma we deduce that almost surely, for sufficiently large . That being true for all , it is true for all with , and from a countable intersection of almost sure events .

Triangular strong law of large numbers

Let and i.i.d. random variables of with . Assume the existence of such that and . Then,

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The being i.i.d. and in , the generalized Marcinkiewicz–Zygmund inequality yields As by assumption, the $O$-lemma concludes the proof.

Remark: The assumptions of the theorem hold as soon as for all and with .

Remark: For , look at Theorem 2.19 of Hall, Heyde Martingal Limit Theory and its application.

Compact strong law of large numbers

Let be a compact subset of with , a measurable space, a random variable taking its values on , and a measurable function defined on . Define on the function , and for all and , the Monte-Carlo average where and are i.i.d. random variables with .

Assume that:

  1. is continuous on ,
  2. there exists a measurable function such that a.s., for all , with ,
  3. .

Then,

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Let and . Write By continuity of there exists such that . For all , By the monotone convergence theorem, there exists such that We easily prove that a.s., . Together with assumption 3. this allows us to apply the triangular strong law of large numbers to , which provides a.s. the existence of such that for all , Together with the definitions of and , this yields the existence a.s. of such that for all , By compacity of , we can extract a finite subcover of with . By finite intersection of almost sure events, there exists a.s. such that for all , That being true for all with , by countable intersection of almost sure events, . The same reasoning with provides .

Remark. If is continuous with respect to the first variable , by Lebesgue's dominated convergence theorem under assumption 2. the function is continuous (i.e. assumption 1. is verified).

world/marcinkiewicz.1642239717.txt.gz · Last modified: 2022/03/16 01:36 (external edit)