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world:forward-downward-martingale

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world:forward-downward-martingale [2026/02/07 08:37]
rdouc
world:forward-downward-martingale [2026/02/07 15:03] (current)
rdouc
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 <WRAP center round tip 80%> <WRAP center round tip 80%>
-Let $U_n[a,b]$ denote the number of completed upcrossings from $a$ to $b$ between times $0$ and $n$.  ​+Let $U_{0:n}[a,b]$ denote the number of completed upcrossings from $a$ to $b$ between times $0$ and $n$.  ​
 Then the following inequality holds: Then the following inequality holds:
 $$ $$
-Y_n \ge (b-a)\,U_n[a,b] - (X_n-a)^-.+Y_n \ge (b-a)\,U_{0:n}[a,b] - (X_n-a)^-.
 $$ $$
  
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 By the upcrossing inequality, for any $a<b$, By the upcrossing inequality, for any $a<b$,
 $$ $$
-(b-a)\,​\mathbb E[U_n[a,b]]+(b-a)\,​\mathbb E[U_{0:n}[a,b]]
 \le \le
 \mathbb E[Y_n] + \mathbb E[(X_n-a)^-]. \mathbb E[Y_n] + \mathbb E[(X_n-a)^-].
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 By the monotone convergence theorem, ​ By the monotone convergence theorem, ​
 $$ $$
-\mathbb E[U_\infty[a,​b]]<​\infty,​+\mathbb E[U_{0:\infty}[a,​b]]<​\infty,​
 $$ $$
 which implies that the total number of upcrossings is almost surely finite.  ​ which implies that the total number of upcrossings is almost surely finite.  ​
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 This is a martingale bounded in $L^1$. This is a martingale bounded in $L^1$.
  
-Similarly as before, we define $C_1=\mathsf{1}_{X_{-n} < a}$ . For all $-n  < k \leq -1$, we set $C_k=\mathsf{1}_{C_{k-1}=1} \mathsf{1}_{X_{k-1} \leq b}+ \mathsf{1}_{C_{k-1}=0} \mathsf{1}_{X_{k-1} <a}$. Define also $Y_k=\sum_{\ell=-n}^k C_\ell (X_\ell - X_{\ell-1})$. Then, for the same reasons, the number of upcrossing $U_n[a,b]$ between $-n$ and $-1$ can be bounded as follows:  ​+Similarly as before, we define $C_1=\mathsf{1}_{X_{-n} < a}$ . For all $-n  < k \leq -1$, we set $C_k=\mathsf{1}_{C_{k-1}=1} \mathsf{1}_{X_{k-1} \leq b}+ \mathsf{1}_{C_{k-1}=0} \mathsf{1}_{X_{k-1} <a}$. Define also $Y_k=\sum_{\ell=-n}^k C_\ell (X_\ell - X_{\ell-1})$. Then, for the same reasons, the number of upcrossing $U_{-n:-1}[a,b]$ between $-n$ and $-1$ can be bounded as follows:  ​
 $$ $$
-Y_{-1} \geq (b-a) U_n[a,b] - (X_{-1}-a)^-+Y_{-1} \geq (b-a) U_{-n:-1}[a,b] - (X_{-1}-a)^-
 $$ $$
  
world/forward-downward-martingale.1770449861.txt.gz · Last modified: 2026/02/07 08:37 by rdouc